Question

If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?

Answer 1

If you dilute 175 mL of a 1.6 M solution of LiCl to 1.0 L, what is the new concentration of the solution?

**Solution:**

Dilution is calculated by the following formula:

$$C _ {1} (L i C l) * V _ {1} (L i C l) = C _ {2} (L i C l) * V _ {2} (L i C l)$$

where $C_1(LiCl)$ is the initial concentration or molarity and $V_{1}(LiCl)$ is the initial volume and $C_2(LiCl)$ is the final concentration or molarity and $V_{2}(LiCl)$ is the final volume.

So,

$$1,6 \text{ mole/ml} * 175 \text{ ml} = C _ {2} (L i C l) * 1000 \text{ ml}$$ $$C _ {2} (L i C l) = \frac {1,6 \text{ mole/ml} * 175 \text{ ml}}{1000 \text{ ml}} = 0,28 \text{ mole/ml}$$

The 1000 mL was used rather than 1.0 l

**Answer:** the concentration of the resulting solution LiCl – 0,28 mole/ml