Answer to Question #305366 in Chemistry for 米乐n

Question

 Fe₂O₃ + 3CO  --> 2Fe +  3CO₂, how many grams of iron are produced when 7.47 grams of iron(III) oxide are reacted?

Answer 1

Solution:

Calculate the moles of iron(III) oxide (Fe₂O₃):

The molar mass of Fe₂O₃ is 159.69 g/mol

Therefore,

Moles of Fe₂O₃ = (7.47 g Fe₂O₃) × (1 mol Fe₂O₃ / 159.69 g Fe₂O₃) = 0.0468 mol Fe₂O₃

Balanced chemical equation:

Fe₂O₃ + 3CO → 2Fe + 3CO₂

According to stoichiometry:

1 mol of Fe₂O₃ produces 2 mol of Fe

Thus, 0.0468 mol of Fe₂O₃ produces:

(0.0468 mol Fe₂O₃) × (2 mol Fe / 1 mol Fe₂O₃) = 0.0936 mol Fe

Calculate the mass of iron (Fe):

The molar mass of Fe is 55.845 g/mol

Therefore,

Mass of Fe = (0.0936 mol Fe) × (55.845 g Fe / 1 mol Fe) = 5.227 g Fe = 5.23 g Fe

Mass of Fe = 5.23 g

Answer: 5.23 grams of iron (Fe) are produced