Answer to Question #303774 in Chemistry for hkc

Question

What mass of zinc is needed to react with 23.1 g of phosphoric acid

Answer 1

3Zn + 2H₃PO₄ = Zn₃(PO₄)₂ + 3H₂

n = m / M

M (H₃PO₄) = 98 g/ mol

M (Zn) = 65.4 g/mol

According to the equation, n (Zn) = 3/2 x n (H₃PO₄)

n (H₃PO₄) = 23.1 / 98 = 0.24 mol

n (Zn) = 3/2 x n (H₃PO₄) = 3/2 x 0.24 = 0.36 mol

m (Zn) = n x M = 0.36 x 65.4 = 23.5 g