Question

1. Calculate the ionic strength of a 0.02 M solution of Al2(SO4)3

Answer 1

[Al³⁺]=2×0.02 M

[SO₄²⁻​]=3×0.02 M

Ionic strength of solution =1/2 x ​[0.02×2×3²+0.02×3×2²] =0.3