how many atoms are in 0.750 moles of zinc
Ifwe have 0.750 moles of Zn, we can use the next formula
n = N/NA
where
n - amount of substance;
N- amount of atoms
NA - the Avogadro constant
N(Zn) = n * NA;
N(Zn) = 0.750 moles * 6.02*10^23 = 4.515 10^23 atoms
Answer: 4.515 10^23 atoms
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