Answer to Question #301046 in Chemistry for Sam

Question

An aliquot of 10 mL from a 12-mol/L aqueous silver solution was transferred into a 100-mL volumetric flask and diluted with water up to the mark. A 10-mL aliquot of the diluted silver solution was transferred into another 100-mL volumetric flask and diluted with water up to the mark. What is the concentration of the final dilution?

Answer 1

C₁ = 12 mol/L

V₁ = 10 mL

C₂ = unknown

V₂ = 100 mL

V₂" = 10 mL

C_f = unknown

V_f = 100 mL

Solution:

Therefore, after the first dilution, the concentration of the solution (С₂) will be:

С₂ = (С₁ × V₁) / V₂ = (12 mol/L × 10 mL) / (100 mL) = 1.2 mol /L

Calculate the concentration of the solution after the final dilution:

С₂ × V₂" = C_f × V_f

C_f = (С₂ × V₂") / V_f = (1.2 mol /L × 10 mL) / (100 mL) = 0.12 mol /L

C_f = 0.12 mol /L

Answer: The concentration of the final dilution is 0.12 mol/L