Answer to Question #300400 in Chemistry for kath

Question

HOW MANY GRAMS SiO2 IS REQUIRED TO PRODUCE 73.8G OF SiC ?

Answer 1

Solution:

Calculate the moles of SiC:

The molar mass of SiC is 40 g/mol

Therefore,

Moles of SiC = (73.8 g SiC) × (1 mol SiC / 40 g SiC) = 1.845 mol

Balanced chemical equation:

SiO₂ + 3C → SiC + 2CO

According to stoichiometry:

1 mol of SiO₂ produces 1 mol of SiC

X mol of SiO₂ produces 1.845 mol of SiC

Thus,

Moles of SiO₂ = X = (1.845 mol SiC) × (1 mol SiO₂ / 1 mol SiC) = 1.845 mol SiO₂

Calculate the mass of SiO₂:

The molar mass of SiO₂ is 60 g/mol

Therefore,

Mass of SiO₂ = (1.845 mol SiO₂) × (60 g SiO₂ / 1 mol SiO₂) = 110.7 g SiO₂

Mass of SiO₂ = 110.7 g

Answer: 110.7 grams of SiO₂ is required.