A container holds 5grams of ccl4 vapour, calculate the volume of ccl4 present
Solution:
The molar mass of CCl4 is 153.82 g/mol
Hence,
Moles of CCl4 = (5 g CCl4) × (1 mol CCl4 / 153.82 g CCl4) = 0.0325 mol CCl4
At STP, one mole of any gas occupies a volume of 22.4 L.
Thus, 0.0325 mol of CCl4 occupies:
(0.0325 mol CCl4) × (22.4 L CCl4 / 1 mol CCl4) = 0.728 L CCl4 = 728 mL CCl4
Answer: The volume of CCl4 is 728 mL
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