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Answer to Question #29692 in Chemistry for Taylor
Question #29692
what would be the best process to figure out a solution to be either potassium iodide or solver nitrate when given only .1M NaCl, .1M Pb(NO3)2, .1M Na2CO3, beakers, flasks, graduated cylinders, filters, filter paper, and balances?
Expert's answer
When adding sodium chloride to silver nitrate the white precipitate of silver chloride is rolled . The process is described by the equation
AgNO3(aq) + NaCl (aq) ------> AgCl + NaNO3
When added to the lead nitrate the solution of potassium iodide the precipitate of lead iodide falls in the form of brilliant golden plates. The process is described by the equation
Pb(NO3)2 + 2KI --> PbI2(s) + 2KNO3
AgNO3(aq) + NaCl (aq) ------> AgCl + NaNO3
When added to the lead nitrate the solution of potassium iodide the precipitate of lead iodide falls in the form of brilliant golden plates. The process is described by the equation
Pb(NO3)2 + 2KI --> PbI2(s) + 2KNO3
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