Answer to Question #296029 in Chemistry for chem chem

Question

If 10.0 liters of oxygen at STP are heated to 512 °C, what will be the new volume of gas if the pressure is also increased to 1520.0 mm of mercury? *

Answer 1

STP = Standard Temperature and Pressure (T = 273.15 K and P = 760 mmHg)

P₁ = 760 mmHg

T₁ = 273.15 K

V₁ = 10.0 L

P₂ = 1520.0 mmHg

T₂ = 512°C = 785.15 K

V₂ = unknown

Solution:

The Combined Gas Law can be used:

P₁V₁/T₁ = P₂V₂/T₂

Cross-multiply to clear the fractions:

P₁V₁T₂ = P₂V₂T₁

Divide to isolate V₂:

V₂ = (P₁V₁T₂) / (P₂T₁)

Plug in the numbers and solve for V₂:

V₂ = (760 mmHg × 10.0 L × 785.15 K) / (1520.0 mmHg × 273.15 K) = 14.4 L

V₂ = 14.4 L

Answer: The new volume of gas will be 14.4 liters.