At s.t.p,a mass of gas occupies a volume of of 802cm³.find the pressure at which the gas occupies 950cm³at 320k
pV = nRT
STP: T = 273 K, p = 1 atm
R = 8.205 m3 atm K−1 mol−1
n = pV / RT = (1 x 0.802) / (8.205 x 273) = 0.0004 mol
p2 = nRT / V = (0.0004 x 8.205 x 302) / 0.905 = 0.98 atm
Comments
Leave a comment