Answer to Question #294106 in Chemistry for jjjjjj

Question #294106

what mass of iron (ll) chloride is needed to produce 12.6 moles of sodium chloride

Expert's answer

FeCl₂ + 2Na = 2NaCl + Fe

According to theequation, n (FeCl₂) = 2 x n (NaCl) = 2 x 12.6 = 25.2 mol

n = m / M

M (FeCl₂) = 126.8 g/mol

m (FeCl₂) = n x M = 25.2 x 126.8 = 3 195.36 g

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