Question

what mass of iron (ll) chloride is needed to produce 12.6 moles of sodium chloride

Answer 1

FeCl₂ + 2Na = 2NaCl + Fe

According to theequation, n (FeCl₂) = 2 x n (NaCl) = 2 x 12.6 = 25.2 mol

n = m / M

M (FeCl₂) = 126.8 g/mol

m (FeCl₂) = n x M = 25.2 x 126.8 = 3 195.36 g