Answer to Question #292419 in Chemistry for Vlei

Question

if xylitol has a chemical formula of c5h12o5, what is the percentage of oxygen in the compound?

Answer 1

Solution:

Xylitol = C₅H₁₂O₅

Atomic mass of elements:

A_r(C) = 12.0107 amu

A_r(H) = 1.00784 amu

A_r(O) = 15.999 amu

Calculate the molar mass of xylitol (C₅H₁₂O₅):

M(C₅H₁₂O₅) = 5×A_r(C) + 12×A_r(H) + 5×A_r(O)

M(C₅H₁₂O₅) = 5×12.0107 + 12×1.00784 + 5×15.999 = 152.1426 (g/mol)

Calculate the percentage of oxygen in the compound:

w(O) = [5×A_r(O) / M(C₅H₁₂O₅)] × 100%

w(O) = [5×15.999 / 152.1426] × 100% = 52.58%

w(O) = 52.58%

Answer: The percentage of oxygen (O) in xylitol (C₅H₁₂O₅) is 52.58%