Answer to Question #291579 in Chemistry for Sheesh

Question

ferric phospate is a pesticide active ingredient used in controlling snails and slugs on food crops. How many grams are in 0.6 mole of F3PO4

Answer 1

n = m / M

m = n x M

M (Fe₃PO₄) = 357.48 g/mol

m (Fe₃PO₄) = 0.6 x 357.48 = 214.5 g