Answer to Question #291001 in Chemistry for lll

Question

Explain how to prepare 400ml of 10 mmol/litre glucose (C₆H₁₂O₆) solution.

 

 

Answer 1

C_M = n / V

n (C₆H₁₂O₆) = C_M x V = 0.010 x 0.4 = 0.004 mol

n = m / M

M (C₆H₁₂O₆) = 180.2 g/mol

m (C₆H₁₂O) = n x M = 0.004 x 180.2 = 0.72 g

0.72 g of C₆H₁₂O₆ and 400 ml of water are required to prepare 400 ml of 10 mmol/litre glucose (C₆H₁₂O₆) solution.