Answer to Question #290579 in Chemistry for hoshi

Question

0.034 kg of potassium iodide in the preparation of a 23.5% potassium iodide solution. Calculate the grams of the water that must added

Answer 1

% = 100 x m_solute / (m_solvent + m_solute)

23.5 = 100 x 0.034 / (m_solvent + 0.034)

m_{solute H2O} = ((100 x 0.034) / 23.5) - 0.034 = 0.11 kg = 110 g