Determine the mass of nitrogen found in 8.85g of Pb(NO3)3
M (Pb(NO3)3) = 331.2 g/mol
M (N) = 14 g/mol
n (Pb(NO3)3) = 8.85 / 331.2 = 0.027 mol
m (N) = 0.027 x 14 x 3 = 1.12 g
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