Answer to Question #289039 in Chemistry for Theresa Stewart

Question

1) Determine the oxidation number if sulfur in the SO⅔-ion and the SO²4 -ion and the use number to name Each ion.

Answer 1

SO₃²⁻ ion: S⁺⁴; O⁻²

1×(+4) + 3×(−2) = 4 + (−6) = (−2) – charge of ion (correct)

The oxidation number of S in SO₃²⁻ ion is +4

SO₃²⁻ is the sulfite ion

SO₄²⁻ ion: S⁺⁶; O⁻²

1×(+6) + 4×(−2) = 6 + (−8) = (−2) – charge of ion (correct)

The oxidation number of S in SO₄²⁻ ion is +6

SO₄²⁻ is the sulfate ion