Answer to Question #287869 in Chemistry for Terony

Question

What mass of copper will be deposited by the liberation of cu +2 when 0.1f of electricity flow through an aqueous solution of copper II salt(cu= 64)

Answer 1

Solution:

Cu²⁺(aq) + 2e⁻ → Cu(s)

From the above-given half-reaction, two moles of electrons react with one mole of Cu²⁺(aq) to deposit one mole of Cu(s). This corresponds to 64 g of copper.

0.1 Faraday's of electricity corresponds to 0.1 moles of electrons.

Hence, they will deposit (0.1 mol e⁻ × 64 g Cu) / (2 mol e⁻) = 3.2 g Cu

Answer: 3.2 grams of copper (Cu) will be deposited