Answer to Question #286940 in Chemistry for Hill

Question

What are the steps involved in calculating how many atoms exist in 100g of lithium?

Answer 1

n = m / M

M (Li) = 6.941 g/mol

n (Li) = 100 / 6.941 = 14.41 mol

1 mol contains 6.022×10²³ elementary entities of the substance.

N (Li) = 14.41 mol x 6.022×10²³ = 86.76 x ×10²³ atoms