In a saturated solution of Al(OH)₃, the concentration of OH⁻ is 2.6 x 10⁻⁵ mol/L. The concentration of Al³⁺ in mol/ L is which of the following?
Solution:
Al(OH)3(s) ⇌ Al3+(aq) + 3OH−(aq)
___S_________S__________3S_____
According to the equation above:
[OH−] = 3S = 2.6×10⁻5 mol/L
Hence,
[Al3+] = S = [OH−] / 3 = (2.6×10−5 mol/L) / 3 = 8.667×10−6 mol/L = 8.7×10−6 mol/L
[Al3+] = 8.7×10−6 mol/L
Answer: 2. 8.7×10−6
Comments
Leave a comment