Answer to Question #286142 in Chemistry for khryst

Question

The end point in a titration of a 50.00 mL sample of HCl solution was reached by the addition of 35.23 mL of 0.250 M NaOH. What is the molarity of the HCl sample?

Answer 1

Solution:

Balanced chemical equation:

HCl(aq) + NaOH(aq) ⟶ NaCl(aq) + H₂O(l)

According to stoichiometry:

1 mol of HCl reacts with 1 mol of NaOH

Moles of solute = Molarity × Volume of solution

Hence,

(Molarity of HCl × 50.00 mL) of HCl reacts with (0.250 M × 35.23 mL) of NaOH

Molarity of HCl × 50.00 mL = 0.250 M × 35.23 mL

Molarity of HCl = (0.250 M × 35.23 mL) / (50.00 mL) = 0.17615 M = 0.176 M

Molarity of HCl = 0.176 M

Answer: The molarity of the HCl sample is 0.176 M