What is the concentration of NaCl in a solution if titration of 15.00 mL of the solution with 0.2503 M AgNO3 requires 20.22 mL of the AgNO3 solution to reach the end point?
AgNO3 (aq) + NaCl (aq) ⟶ AgCl (s) + NaNO3 (aq)
Solution:
Balanced chemical equation:
AgNO3(aq) + NaCl(aq) ⟶ AgCl(s) + NaNO3(aq)
According to stoichiometry:
1 mol of AgNO3 reacts with 1 mol of NaCl
Moles of solute = Molarity × Volume of solution
Hence,
(0.2503 M × 20.22 mL) of AgNO3 reacts with (Molarity of NaCl × 15.00 mL) of NaCl
Molarity of NaCl = (0.2503 M × 20.22 mL) / (15.00 mL) = 0.3374 M
Molarity of NaCl = 0.3374 M
Answer: The concentration of NaCl in a solution is 0.3374 M
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