For the following galvanic cell: Ag(s) | Ag⁺(aq) || Mg²⁺(aq) | Mg(s), which electrode is the anode?
Solution:
1) Ag+(aq) + e− → Ag(s), Eo = +0.80 V
2) Mg2+(aq) + 2e− → Mg(s), Eo = −2.38 V
Eocathode > Eoanode
+0.80 V > −2.38 V
Therefore, Magnesium electrode is the anode
Answer: 2. Mg(s)
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