You need 0.56 mol of electrons to deposit a thin covering of silver on a part that you are using for a prototype machine. How long would you need to run a current of 5.0 A to obtain this number of moles?
Solution:
Ag+ + e- → Ag
Z = 1
Faraday's 1st law can be used:
n = (I × t) / (Z × F)
where:
n = number of moles of electrons (mol)
I = current (A)
t = total time the constant current was applied (s)
Z = number of electrons
F = Faraday constant, 96485 (A s mol-1)
Thus:
t = (n × Z × F) / (I)
t = (0.56 mol × 1 × 96485 A s mol-1) / (5.0 A) = 10806.32 s
t = (10806.32 s) × (1 min / 60 s) = 180 min
t = (10806.32 s) × (1 h / 3600 s) = 3 h
Answer: 3 hours or 180 min or 10806.32 s
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