consider the following reaction :2Al + Cr2O3 = Al2O3 +2cr. what is the mass of Al2O3 that will be produced upon complete reaction of 1.20* 10^21 atoms of Al
2Al + Cr2O3 = Al2O3 +2 Сr
1 mole of matter cntains 6.022×1023 elementary entities.
1.20x1021 atoms of Al equals to 1.20x1021/ 6.022×1023 = 0.2x10-2 moles.
According to the equation, n (Al2O3) = 1/2 x n (Al) = 1/2 x 0.2x10-2 = 0.001 moles.
n = m / M
m = n x M
M (Al2O3) = 102 g/mol
m (Al2O3) = n x M = 0.001 x 102 = 0.102 g
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