how many moles of iron (III) is produced by 0.030 moles of iron in the following reaction 4fe + 3o2- 2fe2o3
Solution:
Balanced chemical equation:
4Fe + 3O2 → 2Fe2O3
According to stoichiometry:
4 mol of iron (Fe) produces 2 mol of iron(III) oxide (Fe2O3)
Thus, 0.030 mol of iron (Fe) produces:
(0.030 mol Fe) × (2 mol Fe2O3 / 4 mol Fe) = 0.015 mol Fe2O3
Answer: 0.015 moles of iron(III) oxide (Fe2O3) is produced
Comments
Leave a comment