Answer to Question #279462 in Chemistry for YAPE

Question #279462

A 4.0520g sample of HCl, specific

Gravity 11.18, required 44.15ml of 0.9035M of Sodium Hydroxide in titration, compute for percent purity.

Expert's answer

n (NaOH) = 44.15 x 0.9035/1000 = 0.04 mol

m (HCl) = 0.04 x 36.5 = 1.46 g of HCl.

%(HCl) = 1.46 x 100/4.052 = 36,0315893 %

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