For a second-order reactant, if the concentration of the reactant is quadrupled, the rate would?
Solution:
A reaction is second order with respect to a reactant.
rate =k[A]2
If the concentration of the reactant is quadrupled, the rate of reaction becomes 16 times.
rate' = k[4 × A]2 = 16k[A]2
Answer: 2) multiply by 16
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