How many grams of NH3 can be made from 6.58 mol of H2 and excess N2?
Solution:
Balanced chemical equation:
N2(g) + 3H2(g) → 2NH3(g)
According to stoichiometry:
3 mol of H2 produces 2 mol of NH3
Thus, 6.58 mol of H2 produces:
(6.58 mol H2) × (2 mol NH3 / 3 mol H2) = 4.387 mol NH3
Calculate the mass of NH3:
The molar mass of NH3 is 17.031 g/mol
Therefore,
(4.387 mol NH3) × (17.031 g NH3 / 1 mol NH3) = 74.7 g NH3
Answer: 74.7 grams of NH3 can be made
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