Balance in acidic medium. Show step by step process.
Iron (solid) reacts with hydrochloric acid (liquid) to form aqueous iron(II) chloride and gaseous
hydrogen.
Solution:
Unbalanced chemical equation (acidic medium):
Fe(s) + HCl(aq) → FeCl2(aq) + H2(g)
Step 1: Separate the half-reactions:
Fe(s) → Fe2+(aq)
H+(aq) → H2(g)
Step 2: Balance elements:
Fe(s) → Fe2+(aq)
2H+(aq) → H2(g)
Step 3: Balance the charge of each equation with electrons.
The iron reaction has no charge on the left side and (2+) on the right side. To balance, add 2 electrons to the right side:
Fe(s) → Fe2+(aq) + 2e−
For the other reaction, there is 2×(1+) = (2+) charge on the left and no charge on the right. So add 2 electrons to the left side:
2H+(aq) + 2e− → H2(g)
Step 4: Scale the reactions so that they have an equal amount of electrons.
In this case, it is already done.
Step 5: Add the reactions and cancel the electrons:
Fe(s) + 2H+(aq) → Fe2+(aq) + H2(g)
Balanced chemical equation:
Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
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