Answer to Question #269660 in Chemistry for Grace

Question

methane(CH⁴) burns in oxygen to produce carbon dioxide and water vapor , what is the number of(CH²) MOLECULES produced when 3.2 L of oxygen are comsumed?

Answer 1

Methane(CH₄) burns in oxygen to produce carbon dioxide and water vapor.

What is the number of (CO₂) molecules produced when 3.2 L of oxygen are comsumed?

Solution:

Calculate the moles of oxygen gas (O₂):

At STP, one mole of any gas occupies a volume of 22.4 L.

Hence,

(3.2 L O₂) × (1 mol O₂ / 22.4 L O₂) = 0.143 mol O₂

Balanced chemical equation:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

According to stoichiometry:

2 mol of O₂ produces 1 mol of CO₂

Thus, 0.143 mol of O₂ produces:

(0.143 mol O₂) × (1 mol CO₂ / 2 mol O₂) = 0.0715 mol CO₂

One mole of any substance contains 6.022×10²³ particles.

Hence,

Number of CO₂ molecules = (0.0715 mol) × (6.022×10²³ molecules / 1 mol) = 4.3×10²² molecules

Number of CO₂ molecules = 4.3×10²² molecules

Answer: 4.3×10²² molecules of CO₂ molecules produced