Answer to Question #268443 in Chemistry for mar

Question

how many molecules of h2o will form with 96.1 g of propane

Answer 1

Solution:

propane = C₃H₈

The molar mass of C₃H₈ is 44.1 g/mol

Hence,

Moles of C₃H₈ = (96.1 g C₃H₈) × (1 mol C₃H₈ / 44.1 g C₃H₈) = 2.179 mol C₃H₈ = 2.18 mol C₃H₈

Balanced chemical equation:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g)

According to stoichiometry:

1 mol of C₃H₈ produces 4 mol of H₂O

Thus, 2.18 mol of C₃H₈ produces:

(2.18 mol C₃H₈) × (4 mol H₂O / 1 mol C₃H₈) = 8.72 mol H₂O

One mole of any substance contains 6.02×10²³ particles.

Hence,

Number of H₂O molecules = (8.72 mol) × (6.02×10²³ molecules / 1 mol) = 5.25×10²⁴ molecules

Number of H₂O molecules = 5.25×10²⁴ molecules

Answer: 5.25×10²⁴ molecules of H₂O will form