Answer to Question #265462 in Chemistry for Momkkok

Question

M(oH)3 equals 78 g/mol what the atomic mass

Answer 1

Solution:

M_r(M(OH)₃) = 78 g/mol

M_r(M(OH)₃) = Ar(M) + 3×Ar(O) + 3×Ar(H)

Ar(H) = 1 g/mol

Ar(O) = 16 g/mol

Therefore,

Ar(M) = M_r(M(OH)₃) - 3×Ar(O) - 3×Ar(H)

Ar(M) = 78 - 3×16 - 3×1 = 27 (g/mol)

Ar(M) = 27 g/mol - aluminium (Al)

Answer: The atomic mass of M is 27 g/mol