Moles of chalk do you have when you have 10 grams before and 8 grams after writing your name?
Solution.
u[CaCO3]=m[CaCO3]/M[CaCO3], on the spelling of the name where spent 10g−8g=2 grams of chalk, then
u[CaCO3]=2/100=0.02 mol.
**Answer:** on the spelling of the name was spent 0.02 mol of chalk.