Answer to Question #26148 in Chemistry for MICHAEL VINCE PADILLA
A 25.0 mL sample of HCL was titrated to the endpoint with 15.0 mL of 2.0 N NaOH.What was the normality of the HCL?What was its molarity
1
2013-03-13T10:05:02-0400
The chemical equation is
NaOH + HCl = NaCl + H2O
According to the equation the amount of NaOH = the amount of HCl
That's why we can write the equation
C(NaOH) x V(NaOH) = C(HCl) x V(HCl)
C(HCl) = C(NaOH) x V(NaOH)/V(HCl) = 2.0 x 15.0 / 25.0 = 1.2 N
For the acids that have only one hydrogen atom the molarity = normality
Answer:
The normality of HCl = 1.2 N
The molarity of HCl = 1.02 M
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