2.0 moles of an idea has are at temperature of -133 degrees Celsius and a pressure of 2atm .what volume in dm3 will the gas occupy at that temperature? R = 0,082 atm, dm3 K -1mol-1
P = 2 atm
V = unknown
n = 2.0 mol
R = 0.082 atm dm3 K-1 mol-1
T = -133°C = 140 К
Solution:
The Ideal Gas equation can be used: PV = nRT
To find the volume of gas, solve the equation for V:
V = nRT / P
V = (2.0 mol × 0.082 atm dm3 K-1 mol-1 × 140 К) / (2 atm) = 11.48 dm3
V = 11.48 dm3
Answer: 11.48 dm3
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