Answer to Question #261273 in Chemistry for Dashia Imtiaz

Question

50 tons of Fe2O3 is reacting with 30 tons of C.

find out mass of Fe extracted?

Volume of Co2 gas released in dm3?

Answer 1

Solution:

The molar mass of Fe₂O₃ is 159.69 g/mol

The molar mass of C is 12.011 g/mol

Determine moles of each reactant:

(50 tons Fe₂O₃) × (1000000 g / 1 ton) × (1 mol Fe₂O₃ / 159.69 g Fe₂O₃) = 313106.64 mol Fe₂O₃

(30 tons C) × (1000000 g / 1 ton) × (1 mol C / 12.011 g C) = 2497710.432 mol C

Balanced chemical equation:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

According to the chemical equation above:

2 mol of Fe₂O₃ reacts with mol of C

Thus, 313106.64 mol of Fe₂O₃ reacts with:

(313106.64 mol Fe₂O₃) × (3 mol C / 2 mol Fe₂O₃) = 469659.96 mol C

However, initially there is 2497710.432 mol of C (according to the task).

Therefore, Fe₂O₃ acts as limiting reagent and C is excess reagent.

According to stoichiometry:

2 mol of Fe₂O₃ produces 4 mol of Fe

Thus, 313106.64 mol of Fe₂O₃ produces:

(313106.64 mol Fe₂O₃) × (4 mol Fe / 2 mol Fe₂O₃) = 626213.28 mol Fe

The molar mass of Fe is 55.845 g/mol

Therefore,

(626213.28 mol Fe) × (55.845 g Fe / 1 mol Fe) = 34970880.62 g Fe

(34970880.62 g Fe) × (1 ton / 1000000 g) = 34.97 tons Fe = 35 tons Fe

According to stoichiometry:

2 mol of Fe₂O₃ produces 3 mol of CO₂

Thus, 313106.64 mol of Fe₂O₃ produces:

(313106.64 mol Fe₂O₃) × (3 mol CO₂ / 2 mol Fe₂O₃) = 469659.96 mol CO₂

At STP, one mole of any gas occupies a volume of 22.4 dm³

Thus, 469659.96 mol of CO₂ occupies:

(469659.96 mol CO₂) × (22.4 dm³ / 1 mol) = 10520383.1 dm³ CO₂ = 10.5×10⁶ dm³ CO₂

Answers:

35 tons of Fe

10.5×10⁶ dm³ of CO₂