Answer to Question #260870 in Chemistry for kaye

Question

given the solid potassium sulfate K2SO4 determine the mass that you need to use to make 50.0mL of 0.750mol/L K2SO4 solution

Answer 1

С_M = n / V

n (K₂SO₄) = C_M x V = 0.750 x 0.0500 = 0.0375 mol

n = m / M

M (K₂SO₄) = 174.3 g/mol

m (K₂SO₄) = n x M = 0.0375 x 174.3 = 6.5 g