Solution:
The molar mass of KClO3 is 122.55 g/mol
The molar mass of O2 is 32.00 g/ mol
Balanced chemical equation:
2KClO3 → 2KCl(s) + 3O2(g)
According to stoichiometry:
3 × Moles of KClO3 = 2 × Moles of O2
Using the mole ration, calculate the mass of oxygen (O2):
(100 g KClO3) × (1 mol KClO3 / 122.55 g KClO3) × (3 mol O2 / 2 mol KClO3) × (32.00 g O2 / 1 mol O2) = 39.168 g O2 = 39.2 g O2
Answer: 39.2 grams of oxygen (O2) can be produced.
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