5.00 g of sodium hydroxide is dissolved in 150 mL of water. Using a coffee-cup calorimeter, the temperature change of the water is measured to be 2.2 degrees celsius. The specific heat capacity of water is 4.184 J/g°C. Calculate the heat released per gram of sodium hydroxide dissolved.
Q = C x m x deltaT
density = m / V
Water density is 1 g/ml. Therefore, 150 ml of water is equal to 150 g.
Q = 4.184 x 150 x 2.2 = 1 380.1 J
The heat released per gram of sodium hydroxide dissolved equals to:
Q1 = 1 380.1 / 5 = 276 J
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