Answer to Question #256627 in Chemistry for wangari

Question

what volume of oxygen will be required to oxidise 1.4 cubic dm of carbon(iv)oxide and what is the volume of the product ,all volumes measured at s.t.p

Answer 1

Solution:

carbon(II) oxide: CO

oxygen gas: O₂

carbon(IV) oxide: CO₂

Balanced chemical equation:

2CO(g) + O₂(g) → 2CO₂(g)

According to stoichiometry:

Moles of CO = 2 × Moles of O₂ = Moles of CO₂

n(CO) = 2 × n(O₂) = n(CO₂)

n = V / V_m

At STP, one mole of any gas occupies a volume of 22.4 dm³ (V_m).

Hence,

V(CO) = 2 × V(O₂) = V(CO₂)

V(CO₂) = V(CO) = 1.4 dm³

V(O₂) = V(CO) / 2 = (1.4 dm³) / 2 = 0.7 dm³

Answer:

V(CO₂) = V(CO) = 1.4 dm³

V(O₂) = 0.7 dm³