Question

what volume of oxygen will be required to oxidise 1.4 cubic dm of carbon(iv)oxide and what is the volume of the product ,all volumes measured at s.t.p

Answer 1

Solution:

carbon(II) oxide: CO

oxygen gas: O₂

carbon(IV) oxide: CO₂

Balanced chemical equation:

2CO(g) + O₂(g) → 2CO₂(g)

According to stoichiometry:

Moles of CO = 2 × Moles of O₂ = Moles of CO₂

n(CO) = 2 × n(O₂) = n(CO₂)

n = V / V_m

At STP, one mole of any gas occupies a volume of 22.4 dm³ (V_m).

Hence,

V(CO) = 2 × V(O₂) = V(CO₂)

V(CO₂) = V(CO) = 1.4 dm³

V(O₂) = V(CO) / 2 = (1.4 dm³) / 2 = 0.7 dm³

Answer:

V(CO₂) = V(CO) = 1.4 dm³

V(O₂) = 0.7 dm³