How many grams of glucose (C6H12O6) are needed to prepare 100mL of a 5% glucose solution?
Let's assume the solution density is 1 g/ml. Therefore, 100 ml = 100 g.
% = (msolute / msolution) x 100%
5% = (msolute / 100) x 100%
msolute = 5 g
The required mass of glucose (C6H12O6) is 5 g.
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