A photographic "stop bath" contains 160mL of pure acetic acid. HC2H3O2(1) in 650 mL solution. What is the v/v concentration of acetic acid in the stop bath?
Solution:
acetic acid = HC2H3O2 - solute
Volume of acetic acid = 160 mL
Volume of the solution = 650 mL
v/v concentration = (solute volume / volume of the solution) × 100%
v/v(HC2H3O2) = (160 mL / 650 mL) × 100% = 24.6%
v/v(HC2H3O2) = 24.6%
Answer: The v/v concentration of acetic acid is 24.6%
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