Answer to Question #252809 in Chemistry for Sophia

Question

42.6 ml of KOH was required to titrate 0.137g H2So4. What is the concentration of the solution.

Answer 1

2KOH + H₂SO₄ = K₂SO₄ + 2H₂O

According to the equation, 1 mole of H₂SO₄ requires 2 moles of KOH.

n = m / M

M (H₂SO₄) = 98.1 g/mol

n (H₂SO₄) = 0.137 / 98.1 = 0.0014 mol

n (KOH) = 2 x n (H₂SO₄) = 2 x 0.0014 = 0.0028 mol

C_M = n / V

C_M (KOH) = 0.0028 / 0.0426 = 0.066 M