Answer to Question #250524 in Chemistry for Zubaria

Question #250524

How to prepare 800 ml of 2 M NaCl solution?

Expert's answer

CM=n/V

n=CMxV

n(NaCl) = 2x0.8=1.6 mol

n=m/M

m(NaCl)= nxM

M(NaCl)=58.44 g/mol

m(NaCl)=1.6 x 58.44 = 93.5 g

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