In the reaction below the oxidising agent is
Na + Cl2 ------> 2NaCl
Solution:
Balanced chemical equation:
2Na + Cl2 ⟶ 2NaCl
Na0 − e− ⟶ Na+
Cl2 + 2e− ⟶ 2Cl−
We see that the oxidation number of chlorine has decreased from 0 in Cl2 to -1 in Cl−
The decrease in oxidation number shows that the Cl2 has been reduced, so Cl2 is the oxidizing agent.
Answer: Cl2 is the oxidizing agent.
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