Question #24955
How many moles of HF are required to dissolve 6.9 moles of sodium dilicate in this reaction?
Expert's answer
The reaction between HF and Na2SiO3 is:
8HF+Na2SiO3=2NaF+ H2SiF6+3H2O.
Based on this equation of reaction 1 mole of Na2SiO3 reacts with 8 moles of HF, so with 6.9 moles of Na2SiO3 will react 8•6.9=55.2 moles of HF.
Answer:
The number of moles of HF is 55.2.
8HF+Na2SiO3=2NaF+ H2SiF6+3H2O.
Based on this equation of reaction 1 mole of Na2SiO3 reacts with 8 moles of HF, so with 6.9 moles of Na2SiO3 will react 8•6.9=55.2 moles of HF.
Answer:
The number of moles of HF is 55.2.
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#339914 on Dec 2023
#339914 on Dec 2023
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