Question #24955
How many moles of HF are required to dissolve 6.9 moles of sodium dilicate in this reaction?
Expert's answer
The reaction between HF and Na2SiO3 is:
8HF+Na2SiO3=2NaF+ H2SiF6+3H2O.
Based on this equation of reaction 1 mole of Na2SiO3 reacts with 8 moles of HF, so with 6.9 moles of Na2SiO3 will react 8•6.9=55.2 moles of HF.
Answer:
The number of moles of HF is 55.2.
8HF+Na2SiO3=2NaF+ H2SiF6+3H2O.
Based on this equation of reaction 1 mole of Na2SiO3 reacts with 8 moles of HF, so with 6.9 moles of Na2SiO3 will react 8•6.9=55.2 moles of HF.
Answer:
The number of moles of HF is 55.2.
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
#340153 on Dec 2023
#340153 on Dec 2023