How many moles of HF are required to dissolve 6.9 moles of sodium dilicate in this reaction?
1
Expert's answer
2013-02-27T07:03:47-0500
To answer this question we are to write down the reaction and to put the coefficients: 2HF+Na2SiO3=2NaF+H2SiO3 So we can see that the amount of HF is two times more than Na2SiO3. If we have 6.9 moles of sodium silicate the amount of HF is: 6.9 /2=3,45 moles
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