Question

Sir i have to prepare solution of molar ratio for FeCl3/Pyrrole is 2.2 (Mol.wt of FeCl3 is 162.2 and Mol. wt of pyrrole is 67.09) in 30 ml distilled water and FeCl3 concentration is 14wt%. Please tell me how much pyrrole has taken and how to calculate it. Please reply me soon. Thanks

Answer 1

If you will take 30 ml of aqua (water) solution of FeCl3 with concentration 14 wt%, the mass of& FeCl3 in this solution will be: 30•0.14=4.2 g. So that, the number moles of FeCl3 are: 4.2/162.2=0.026 moles. The number moles of Pyrrole are: 0.026/2.2=0.011 moles (if the ratio FeCl3: Pyrrole is 2.2:1), and mass Pyrrole which you should take: 0.011•67.09=0.79 g.

Answer: the mass pyrrole is 0.79 g.